If and object is thrown upward, dropped, or thrown downward and travels in a straight line subject only to gravity, the height h of the object above the ground (in feet) after t seconds is given by h=-16t^2+vt+h, where h is the height of the object when t=0 and v is the velocity of the object at time t=0. Note that the value of v is taken to be positive if the object moves upward and negative if it moves downward. A ball is thrown upward from ground level wit an initial velocity of 64 ft per second. In how may seconds will the ball reach the given height? a) 64ft b)60ft
If and object is thrown upward, dropped, or thrown downward and travels in a straight line subject only to gravity,…
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