Hey, I need help with this questions please, they are quite easy, but there are so many of them

.

–/1 points

SPreCalc7 6.3.002.

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The sign of a trigonometric function of θ depends on the —Select— axis quadrant in/on which the terminal side of the angle lies.In Quadrant II, sin(θ) is —Select— positive negative .

In Quadrant III, cos(θ) is —Select— positive negative .

In Quadrant IV, tan(θ) is —Select— positive negative .

2.

–/1 points

SPreCalc7 6.3.003.

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(a) If θ is in standard position, then the reference angle θ

is the acute angle formed by the terminal side of
θ and the
—Select— x-axis y-axis . So the reference angle for

θ = 110°

is

θ = °,

and that for

θ = 190°

is

θ = °.

(b) If θ is any angle, the value of a trigonometric function of θ is the same, except possibly for sign, as the value of the trigonometric function of

θ.

So

sin(110°) = sin

°

, and

sin(190°) = −sin

°

.

3.

–/1 points

SPreCalc7 6.3.007.

My Notes

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Find the reference angle for the given angle.(a)265°
°

(b)820°

°

(c) −95°

°

4.

–/1 points

SPreCalc7 6.3.011.

My Notes

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Find the reference angle for the given angle.(a)

3Ï€

5

(b)

−0.8π

(c)

0.8

5.

–/1 points

SPreCalc7 6.3.015.

My Notes

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Find the exact value of the trigonometric function. (If an answer is undefined, enter UNDEFINED.)tan(150°)

6.

–/1 points

SPreCalc7 6.3.018.

My Notes

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Find the exact value of the trigonometric function. (If an answer is undefined, enter UNDEFINED.)csc(240°)

7.

–/1 points

SPreCalc7 6.3.025.

My Notes

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Find the exact value of the trigonometric function. (If an answer is undefined, enter UNDEFINED.)sin

3Ï€

2

8.

–/1 points

SPreCalc7 6.3.029.

My Notes

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Find the exact value of the trigonometric function. (If an answer is undefined, enter UNDEFINED.)csc

−

Ï€

6

9.

–/1 points

SPreCalc7 6.3.034.

My Notes

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Find the exact value of the trigonometric function. (If an answer is undefined, enter UNDEFINED.)cos

3Ï€

4

10.

–/1 points

SPreCalc7 6.3.039.

My Notes

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Find the quadrant in which θ lies from the information given.sec(θ) < 0 and tan(θ) < 0

III IIIIV

11.

–/1 points

SPreCalc7 6.3.041.

My Notes

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Write the first trigonometric function in terms of the second for θ in the given quadrant.tan(θ), cos(θ); θ in Quadrant III

tan(
θ) =

12.

–/1 points

SPreCalc7 6.3.043.

My Notes

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Write the first trigonometric function in terms of the second for θ in the given quadrant.cos(θ), sin(θ); θ in Quadrant IV

cos(
θ) =

13.

–/1 points

SPreCalc7 6.3.049.

My Notes

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Find the values of the trigonometric functions of θ from the information given.cos(θ) =

4

19

, sin(
θ) < 0

sin(θ)	=
tan(θ)	=
csc(θ)	=
sec(θ)	=
cot(θ)	=

14.

–/1 points

SPreCalc7 6.3.051.

My Notes

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Find the values of the trigonometric functions of θ from the information given.csc(θ) = 4,

θ in Quadrant I

sin(θ)	=
cos(θ)	=
tan(θ)	=
sec(θ)	=
cot(θ)	=

15.

–/1 points

SPreCalc7 6.3.056.

My Notes

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If θ = π/4,

find the value of each expression. (Round your answers to three decimal places, if necessary.)

sin2(θ)	=
sin(θ2)	=

16.

–/1 points

SPreCalc7 6.3.058.

My Notes

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Find the area of a triangle with the given description. (Round your answer to one decimal place.)a triangle with sides of length 12 and 23 and included angle 20°

17.

–/1 points

SPreCalc7 6.3.059.MI.

My Notes

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Find the area of the triangle with the given description. (Round your answer to one decimal place.)an equilateral triangle with side of length 14

18.

–/1 points

SPreCalc7 6.3.063.

My Notes

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Find the area of the shaded region in the figure. (Round your answer to two decimal places.)

19.

–/1 points

SPreCalc7 6.3.067.

My Notes

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A graphing calculator is recommended.

A rectangular beam is to be cut from a cylindrical log of diameter d = 22 cm. The figures show different ways this can be done.

(a) Express the cross-sectional area of the beam as a function of the angle θ in the figures.
A(θ) =

(b) Graph the function you found in part (a).

(c) Find the dimensions of the beam with largest cross-sectional area. (Round your answers to two decimal places.)

width	cm
depth	cm

20.

–/1 points

SPreCalc7 6.3.068.

My Notes

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The strength of a beam is proportional to the width and the square of the depth. A beam is cut from a cylindrical log of diameter d = 20 cm. The figures show different ways this can be done. Express the strength of the beam as a function of the angle θ in the figures. (Use k as your proportionality constant.)
S(θ) =

<a c